The x-component motion is rather uninteresting -- constant x-position, thus zero x-velocity,
and zero x-acceleration.
Note the direct relationship between the ball's height and the value of Y on the y-component
position graph.
Note the relationship between the velocity vector and the slope of the Y vs. t curve:
As the velocity vector gets shorter on
the way up, the positive slope of the Y vs. t curve becomes
less.
As the velocity vector gets longer on the way down, the y vs. t curve gets steeper, with
negative slope.
The ball's speed decreases as it rises, and increases as it falls; thus the acceleration
is downward. This can also be inferred from the negative slope of the Vy vs. t graph and
zero slope of the Vx vs. t graph
The y-component of the velocity (which is the total velocity in this case)
is zero at the maximum height, but the acceleration (slope
of the velocity curve) is not zero there.